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FindAdv: Amend 652ffc9c(2): Fix handling search for whole words if in mathed.

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Didn't know, how to get char-value cursor is pointing to.
Hopefully someone knows a better way as in this patch.
This commit is contained in:
Kornel Benko 2022-05-28 21:17:13 +02:00
parent 52c5084d63
commit 0d6e3bcdc3
1 changed files with 36 additions and 2 deletions
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38
src/lyxfind.cpp
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@ -4831,6 +4831,10 @@ static int findAdvReplace(BufferView * bv, FindAndReplaceOptions const & opt, Ma
return 1;
}
static bool isWordChar(char_type c)
{
return isLetterChar(c) || isDigitASCII(c);
}
/// Perform a FindAdv operation.
bool findAdv(BufferView * bv, FindAndReplaceOptions & opt)
@ -4860,7 +4864,7 @@ bool findAdv(BufferView * bv, FindAndReplaceOptions & opt)
if (opt.matchword && cur.pos() > 0) { // Skip word-characters if we are in the mid of a word
if (cur.inTexted()) {
Paragraph const & par = cur.paragraph();
if ((cur.pos() > 0) && !par.isWordSeparator(cur.pos() -1, true)) {
if (!par.isWordSeparator(cur.pos() -1, true)) {
class Text *t = cur.text();
CursorSlice to;
CursorSlice from = cur.top();
@ -4870,7 +4874,37 @@ bool findAdv(BufferView * bv, FindAndReplaceOptions & opt)
}
}
else if (cur.inMathed()) {
cur.pos() = cur.lastpos();
// Check if 'cur.pos()-1' and 'cur.pos()' both point to a letter,
// I am not sure, we should consider the selection
bool sel = bv->cursor().selection();
if (!sel && cur.pos() < cur.lastpos()) {
CursorSlice const & cs = cur.top();
MathData md = cs.cell();
int len = -1;
MathData::const_iterator it_end = md.end();
MathData md2;
// Start the check with one character before actual cursor position
for (MathData::const_iterator it = md.begin() + cs.pos() - 1;
it != it_end; ++it)
md2.push_back(*it);
docstring inp = asString(md2);
LYXERR0("Got \"" << inp << "\"");
char_type prev = inp[0];
for (len = 0; (unsigned) len < inp.size() && len + cur.pos() <= cur.lastpos(); len++) {
char_type c = inp[len];
if (isLetterChar(c))
continue;
if (isDigitASCII(c))
continue;
break;
}
// len == 0 means previous char was a word separator
// len == 1 search starts with a word separator
// len == 2 ... we have to skip len -1 chars
if (len > 1)
cur.pos() = cur.pos() + len - 1;
}
}
opt.matchword = false;
}