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Refactor the code to split a string into an argv array of words to pass
to execvp. git-svn-id: svn://svn.lyx.org/lyx/lyx-devel/trunk@9568 a592a061-630c-0410-9148-cb99ea01b6c8
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@ -1,3 +1,9 @@
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2005-02-02 Angus Leeming <leeming@lyx.org>
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* forkedcall.C (generateChild): overhaul the code to split a string
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into an argv array of words. Now respects simple quoting reasonably
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well.
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2005-02-01 Angus Leeming <leeming@lyx.org>
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* fs_extras.C: #include <windows.h>
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@ -257,48 +257,60 @@ int Forkedcall::generateChild()
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return 1;
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// Split the input command up into an array of words stored
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// in a contiguous block of memory.
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char const * const c_str = line.c_str();
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// in a contiguous block of memory. The array contains pointers
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// to each word.
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// Don't forget the terminating `\0' character.
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char const * const c_str = line.c_str();
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vector<char> vec(c_str, c_str + line.size() + 1);
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// Turn the string into an array of words, each terminated with '\0'.
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std::replace(vec.begin(), vec.end(), ' ', '\0');
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// Build an array of pointers to each word.
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vector<char>::iterator vit = vec.begin();
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vector<char>::iterator vend = vec.end();
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vector<char *> argv;
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char prev = '\0';
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for (; vit != vend; ++vit) {
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if (*vit != '\0' && prev == '\0')
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argv.push_back(&*vit);
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prev = *vit;
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}
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// Strip quotes. Does so naively, assuming that the word begins
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// and ends in quotes.
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vector<char *>::iterator ait = argv.begin();
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vector<char *>::iterator const aend = argv.end();
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for (; ait != aend; ++ait) {
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char * word = *ait;
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std::size_t const len = strlen(word);
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if (len >= 2) {
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char & first = word[0];
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char & last = word[len-1];
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if (first == last &&
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(first == '\'' || first == '"')) {
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first = '\0';
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last = '\0';
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*ait += 1;
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// Splitting the command up into an array of words means replacing
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// the whitespace between words with '\0'. Life is complicated
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// however, because words protected by quotes can contain whitespace.
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//
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// The strategy we adopt is:
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// 1. If we're not inside quotes, then replace white space with '\0'.
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// 2. If we are inside quotes, then don't replace the white space
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// but do remove the quotes themselves. We do this naively by
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// replacing the quote with '\0' which is fine if quotes
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// delimit the entire word.
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char inside_quote = 0;
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vector<char>::iterator it = vec.begin();
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vector<char>::iterator const end = vec.end();
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for (; it != end; ++it) {
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char const c = *it;
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if (!inside_quote) {
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if (c == ' ')
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*it = '\0';
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else if (c == '\'' || c == '"') {
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*it = '\0';
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inside_quote = c;
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}
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} else if (c == inside_quote) {
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*it = '\0';
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inside_quote = 0;
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}
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}
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ait = argv.begin();
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for (; ait != aend; ++ait)
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std::cout << *ait << std::endl;
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// Build an array of pointers to each word.
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it = vec.begin();
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vector<char *> argv;
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char prev = '\0';
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for (; it != end; ++it) {
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if (*it != '\0' && prev == '\0')
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argv.push_back(&*it);
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prev = *it;
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}
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argv.push_back(0);
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// Debug output.
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vector<char *>::iterator ait = argv.begin();
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vector<char *>::iterator const aend = argv.end();
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lyxerr << "<command>\n";
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for (; ait != aend; ++ait)
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if (*ait)
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lyxerr << '\t'<< *ait << '\n';
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lyxerr << "</command>" << std::endl;
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#ifndef __EMX__
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pid_t const cpid = ::fork();
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if (cpid == 0) {
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