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Make doExport() helper private
One declaration of doExport() was not used, and the other one was only used by Buffer, so make it private since returning the exported file name is a bit strange if it can also appear as input argument.
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@ -643,20 +643,17 @@ public:
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///
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ExportStatus doExport(std::string const & target, bool put_in_tempdir) const;
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///
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ExportStatus doExport(std::string const & target, bool put_in_tempdir,
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std::string & result_file) const;
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///
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ExportStatus preview(std::string const & format) const;
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private:
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///
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ExportStatus doExport(std::string const & target, bool put_in_tempdir,
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std::string & result_file) const;
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/// target is a format name optionally followed by a space
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/// and a destination file-name
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ExportStatus doExport(std::string const & target, bool put_in_tempdir,
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bool includeall, std::string & result_file) const;
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///
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ExportStatus doExport(std::string const & target, bool put_in_tempdir,
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bool includeall) const;
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///
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ExportStatus preview(std::string const & format, bool includeall = false) const;
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///
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void setMathFlavor(OutputParams & op) const;
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