Allow to type a space in front of another one

This is a follow-up to 714b731e. This fixes the issue when the cursor
is in front of a space
  abc| def
and one inserts another space (to start a word). DEPM would eat one
space and produce
  abc |def
instead of
  abc | def

Additionally, fix the same_par boolean, wheich did not take the cell
index into account.

Related to ticket #11412.
This commit is contained in:
Jean-Marc Lasgouttes 2019-01-14 16:37:10 +01:00
parent 0594a4fe72
commit 7848d3c90c

View File

@ -819,8 +819,8 @@ bool Text::deleteEmptyParagraphMechanism(Cursor & cur,
There are still some small problems that can lead to There are still some small problems that can lead to
double spaces stored in the document file or space at double spaces stored in the document file or space at
the beginning of paragraphs(). This happens if you have the beginning of paragraphs(). This happens if you have
the cursor between to spaces and then save. Or if you the cursor between two spaces and then save. Or if you
cut and paste and the selection have a space at the cut and paste and the selection has a space at the
beginning and then save right after the paste. (Lgb) beginning and then save right after the paste. (Lgb)
*/ */
@ -840,7 +840,8 @@ bool Text::deleteEmptyParagraphMechanism(Cursor & cur,
// Whether a common inset is found and whether the cursor is still in // Whether a common inset is found and whether the cursor is still in
// the same paragraph (possibly nested). // the same paragraph (possibly nested).
bool const same_par = depth < cur.depth() && old.pit() == cur[depth].pit(); bool const same_par = depth < cur.depth() && old.idx() == cur[depth].idx()
&& old.pit() == cur[depth].pit();
bool const same_par_pos = depth == cur.depth() - 1 && same_par bool const same_par_pos = depth == cur.depth() - 1 && same_par
&& old.pos() == cur[depth].pos(); && old.pos() == cur[depth].pos();
@ -863,7 +864,7 @@ bool Text::deleteEmptyParagraphMechanism(Cursor & cur,
if (from != to && from > 0 && to < oldpar.size()) if (from != to && from > 0 && to < oldpar.size())
++from; ++from;
if (same_par && cur.pos() > from && cur.pos() < to) if (same_par && cur.pos() >= from && cur.pos() < to)
++from; ++from;
// Remove spaces and adapt cursor. // Remove spaces and adapt cursor.