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More fixes to cursorX

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In Row::Element::pos2x, handle the boundaries in a cleaner way.
This commit is contained in:
Jean-Marc Lasgouttes 2013-10-18 17:55:30 +02:00
parent 8649ac7fe6
commit 79014c7551
2 changed files with 18 additions and 11 deletions
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22
src/Row.cpp
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@ -36,17 +36,23 @@ using frontend::FontMetrics;
double Row::Element::pos2x(pos_type const i) const
{
LASSERT(i >= pos && i <= endpos, return 0);
bool const rtl = font.isVisibleRightToLeft();
// handle first the two bounds of the element
if ((!rtl && pos >= i) || (rtl && endpos <= i))
return 0;
if ((!rtl && endpos <= i) || (rtl && pos >= i))
return width();
int w = 0;
//handle first the two bounds of the element
if (i == pos)
w = 0;
else if (i == endpos)
w = width();
else {
LASSERT(type == STRING, return 0);
FontMetrics const & fm = theFontMetrics(font);
// FIXME Avoid caching of metrics there?
w = fm.width(str.substr(0, i - pos));
}
FontMetrics const & fm = theFontMetrics(font);
// FIXME Avoid caching of metrics there?
int const w = fm.width(str.substr(0, i - pos));
if (rtl)
return width() - w;
else

7
src/TextMetrics.cpp
View File

@ -1613,15 +1613,16 @@ int TextMetrics::cursorX(CursorSlice const & sl,
double x = row.x;
/**
* When boundary is true, position is on the row element (pos, endpos)
* When boundary is true, position i is in the row element (pos, endpos)
* if
* pos < pos <= endpos
* pos < i <= endpos
* whereas, when boundary is false, the test is
* pos <= pos < endpos
* pos <= i < endpos
* The correction below allows to handle both cases.
*/
int const boundary_corr = (boundary && pos) ? -1 : 0;
//?????
if (row.empty()
|| (row.begin()->font.isVisibleRightToLeft()
&& pos == row.begin()->endpos))