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Do not break row at inset boundary if possible

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The first change is to concentrate on the last ro elements that contain separators and try to break it a a width that is shorter than both
- its current width (we want to break it, after all)
- the amount of space available.

This simple heuristic seems to give good results.
This commit is contained in:
Jean-Marc Lasgouttes 2015-07-22 11:05:02 +02:00
parent bdc9977264
commit 7d19265ba0
1 changed files with 32 additions and 17 deletions
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49
src/Row.cpp
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@ -382,13 +382,44 @@ void Row::shortenIfNeeded(pos_type const keep, int const w)
Elements::iterator const end = elements_.end();
int wid = left_margin;
// The last breakable element that has been found and its x position.
Elements::iterator last_brk = elements_.end();
int last_wid = 0;
Elements::iterator cit = beg;
for ( ; cit != end ; ++cit) {
if (cit->endpos >= keep && wid + cit->dim.wid > w)
if (cit->countSeparators() && cit->pos >= keep) {
last_brk = cit;
last_wid = wid;
}
if (wid + cit->dim.wid > w)
break;
wid += cit->dim.wid;
}
/* We have found a suitable separable element. This is the common case.
* Try to break it cleanly (at word boundary) at a length that is both
* - less than the available space on the row
* - shorter than the natural width of the element, in order to enforce
* break-up.
*/
if (last_brk != end
&& last_brk->breakAt(min(w - last_wid, last_brk->dim.wid - 2), false)) {
end_ = last_brk->endpos;
/* after breakAt, there may be spaces at the end of the
* string, but they are not counted in the string length
* (QTextLayout feature, actually). We remove them, but do not
* change the endo of the row, since the spaces at row break
* are invisible.
*/
last_brk->str = rtrim(last_brk->str);
last_brk->endpos = last_brk->pos + last_brk->str.length();
dim_.wid = last_wid + last_brk->dim.wid;
// If there are other elements, they should be removed.
elements_.erase(next(last_brk, 1), end);
return;
}
if (cit == end) {
// This should not happen since the row is too long.
LYXERR0("Something is wrong cannot shorten row: " << *this);
@ -402,22 +433,6 @@ void Row::shortenIfNeeded(pos_type const keep, int const w)
wid -= cit->dim.wid;
}
// Try to break this row cleanly (at word boundary)
if (cit->breakAt(w - wid, false)) {
end_ = cit->endpos;
// after breakAt, there may be spaces at the end of the
// string, but they are not counted in the string length
// (qtextlayout feature, actually). We remove them, but do not
// change the endo of the row, since the spaces at row break
// are invisible.
cit->str = rtrim(cit->str);
cit->endpos = cit->pos + cit->str.length();
dim_.wid = wid + cit->dim.wid;
// If there are other elements, they should be removed.
elements_.erase(next(cit, 1), end);
return;
}
if (cit != beg) {
// There is no separator, but several elements have been
// added. We can cut right here.