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Clean and speedup code in revert_unicode
git-svn-id: svn://svn.lyx.org/lyx/lyx-devel/trunk@19145 a592a061-630c-0410-9148-cb99ea01b6c8
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@ -1884,25 +1884,21 @@ implemented.'''
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spec_chars = read_unicodesymbols()
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# Define strings to start and end ERT and math insets
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ert_intro='\n\n\\begin_inset ERT\nstatus collapsed\n\\begin_layout %s\n\\backslash\n' % document.default_layout
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ert_outro='\n\\end_layout\n\n\\end_inset\n\n'
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ert_intro='\n\n\\begin_inset ERT\nstatus collapsed\n\\begin_layout %s\n\\backslash' % document.default_layout
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ert_outro='\n\\end_layout\n\n\\end_inset\n'
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math_intro='\n\\begin_inset Formula $'
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math_outro='$\n\\end_inset\n'
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math_outro='$\n\\end_inset'
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# Find unicode characters and replace them
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in_ert = False # flag set to 1 if in ERT inset
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in_math = False # flag set to 1 if in math inset
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insets = [] # list of active insets
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mod_body = u'' # to store the modified document body
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# Go through the file to capture all combining characters
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last_char = '' # to store the previous character
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body_string = u'' # store the document temporarily as a string
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for line in document.body:
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body_string = body_string + line +'\n'
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[body_string, apa] = body_string.rsplit('\n',1)
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body = body_string.split('\n')
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for line in body:
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i = 0
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while i < len(document.body):
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line = document.body[i]
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# Check for insets
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if line.find('\\begin_inset') > -1:
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# check which inset to start
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@ -1931,40 +1927,44 @@ implemented.'''
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try:
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# If all goes well the line is written here
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dummy = line.encode(document.encoding)
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mod_body = mod_body + line + '\n'
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last_char = line[-1]
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i += 1
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except:
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# Error, some character(s) in the line need to be replaced
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mod_line = u''
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for character in line:
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try:
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# Try to write the character
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dummy = character.encode(document.encoding)
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mod_body = mod_body + character
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mod_line += character
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last_char = character
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except:
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# Try to replace with ERT/math inset
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if spec_chars.has_key(character):
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command = spec_chars[character][0]; # the command to replace unicode
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command = spec_chars[character][0] # the command to replace unicode
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flag1 = spec_chars[character][1]
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flag2 = spec_chars[character][2]
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if flag1.find('combining') > -1 or flag2.find('combining') > -1:
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# We have a character that should be combined with the previous
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command = command + '{' +last_char + '}'
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command += '{' + last_char + '}'
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# Remove the last character. Ignore if it is whitespace
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if len(last_char.rstrip()) > 0:
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if len(last_char.rstrip()):
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# last_char was found and is not whitespace
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[mod_body, apa] = mod_body.rsplit(last_char,1)
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if mod_line:
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mod_line = mod_line[:-1]
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else: # last_char belongs to the last line
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document.body[i-1] = document.body[i-1][:-1]
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else:
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# The last character was replaced by a command. For now it is
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# ignored. This could be handled better.
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pass
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if command[0:2] == '\\\\':
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if command[2:12]=='ensuremath':
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if in_ert == True:
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if in_ert:
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# math in ERT
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command = command.replace('\\\\ensuremath{\\\\', '$\n\\backslash\n')
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command = command.replace('\\\\ensuremath{\\\\', '$\n\\backslash')
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command = command.replace('}', '$\n')
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elif in_math == False:
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elif not in_math:
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# add a math inset with the replacement character
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command = command.replace('\\\\ensuremath{\\', math_intro)
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command = command.replace('}', math_outro)
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@ -1973,23 +1973,23 @@ implemented.'''
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command = command.replace('\\\\ensuremath{\\', '')
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command = command.replace('}', '')
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else:
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if in_math == True:
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if in_math:
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# avoid putting an ERT in a math; instead put command as text
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command = command.replace('\\\\', '\mathrm{')
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command = command + '}'
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elif in_ert == False:
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elif not in_ert:
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# add an ERT inset with the replacement character
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command = command.replace('\\\\', ert_intro)
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command = command + ert_outro
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else:
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command = command.replace('\\\\', '\n\\backslash\n')
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command = command.replace('\\\\', '\n\\backslash')
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last_char = '' # indicate that the character should not be removed
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mod_body = mod_body + command
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mod_line += command
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else:
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# Replace with replacement string
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mod_body = mod_body + replacement_character
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[mod_body, apa] = mod_body.rsplit('\n',1)
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document.body = mod_body.split('\n')
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mod_line += replacement_character
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document.body[i:i+1] = mod_line.split('\n')
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i += len(mod_line.split('\n'))
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##
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