Another minor change, but this should almost get us to the point that we

could return all paths, not just one.


git-svn-id: svn://svn.lyx.org/lyx/lyx-devel/trunk@31915 a592a061-630c-0410-9148-cb99ea01b6c8
This commit is contained in:
Richard Heck 2009-11-09 03:43:48 +00:00
parent dfbbb87e0b
commit ac6a58071e

View File

@ -44,6 +44,11 @@ vector<int> const
if (!bfs_init(target, clear_visited))
return result;
// Here's the logic, which is shared by the other routines.
// Q_ holds a list of nodes we have been able to reach (in this
// case, reach backwards). It is initailized to the current node
// by bfs_init, and then we recurse, adding the nodes we can reach
// from the current node as we go.
while (!Q_.empty()) {
int const current = Q_.front();
Q_.pop();
@ -142,8 +147,8 @@ Graph::EdgePath const Graph::getPath(int from, int to)
if (to < 0 || !bfs_init(from))
return path;
vector<int> prev_edge(formats.size());
vector<int> prev_vertex(formats.size());
// pair<vertex, edge>
vector<pair<int, int> > prev(vertices_.size());
bool found = false;
while (!Q_.empty()) {
@ -164,8 +169,9 @@ Graph::EdgePath const Graph::getPath(int from, int to)
if (!visited_[cv]) {
visited_[cv] = true;
Q_.push(cv);
prev_edge[cv] = cit->edge;
prev_vertex[cv] = current;
// FIXME This will not do for finding multiple paths.
// Perhaps we need a vector, or a set.
prev[cv] = pair<int, int>(current, cit->edge);
}
}
}
@ -173,8 +179,8 @@ Graph::EdgePath const Graph::getPath(int from, int to)
return path;
while (to != from) {
path.push_back(prev_edge[to]);
to = prev_vertex[to];
path.push_back(prev[to].second);
to = prev[to].first;
}
reverse(path.begin(), path.end());
return path;