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Fix some row breaking problems with large insets
When a row is too large due to a wide inset, it does not make sense to break text before if the problem is the same in the next row. Therefore give up breaking in this case. Note that this was explicitely taken care of in the old-world rowBreakPoint code. Fixes bug #9691.
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parent
125a297778
commit
f921c2e8ec
13
src/Row.cpp
13
src/Row.cpp
@ -404,7 +404,8 @@ void Row::shortenIfNeeded(pos_type const keep, int const w)
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++cit_brk;
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while (cit_brk != beg) {
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--cit_brk;
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Element & brk = *cit_brk;
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// make a copy of the element to work on it.
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Element brk = *cit_brk;
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wid_brk -= brk.dim.wid;
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if (brk.countSeparators() == 0 || brk.pos < keep)
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continue;
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@ -415,6 +416,15 @@ void Row::shortenIfNeeded(pos_type const keep, int const w)
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* break-up.
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*/
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if (brk.breakAt(min(w - wid_brk, brk.dim.wid - 2), false)) {
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/* if this element originally did not cause a row overflow
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* in itself, and the remainder of the row would still be
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* too large after breaking, then we will have issues in
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* next row. Thus breaking does not help.
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*/
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if (wid_brk + cit_brk->dim.wid < w
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&& dim_.wid - (wid_brk + brk.dim.wid) >= w) {
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break;
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}
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end_ = brk.endpos;
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/* after breakAt, there may be spaces at the end of the
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* string, but they are not counted in the string length
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@ -424,6 +434,7 @@ void Row::shortenIfNeeded(pos_type const keep, int const w)
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*/
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brk.str = rtrim(brk.str);
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brk.endpos = brk.pos + brk.str.length();
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*cit_brk = brk;
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dim_.wid = wid_brk + brk.dim.wid;
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// If there are other elements, they should be removed.
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elements_.erase(cit_brk + 1, end);
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